(PHP 5, PHP 7)
strpbrk — 在字符串中查找一组字符的任何一个字符
$haystack
, string $char_list
)
strpbrk() 函数在 haystack 字符串中查找 char_list 中的字符。
haystack
在此字符串中查找 char_list。
char_list该参数区分大小写。
返回一个以找到的字符开始的子字符串。如果没有找到，则返回 FALSE。
Example #1 strpbrk() 范例
<?php
$text = 'This is a Simple text.';
// 输出 "is is a Simple text."，因为 'i' 先被匹配
echo strpbrk($text, 'mi');
// 输出 "Simple text."，因为字符区分大小写
echo strpbrk($text, 'S');
?>
A little modification to Evan's code to use an array for the second parameter :
<?php
function strpbrkpos($s, $accept) {
$r = FALSE;
$t = 0;
$i = 0;
$accept_l = count($accept);
for ( ; $i < $accept_l ; $i++ )
if ( ($t = strpos($s, $accept[$i])) !== FALSE )
if ( ($r === FALSE) || ($t < $r) )
$r = $t;
return $r;
}
?>
If you're not looking to duplicate the rest of the string, but instead just want the offset, in the spirit of the str*pos() functions, use strcspn()
If you're not looking to duplicate the rest of the string, but instead just want the offset, in the spirit of the str*pos() functions:
<?php
function strpbrkpos($s, $accept) {
$r = FALSE;
$t = 0;
$i = 0;
$accept_l = strlen($accept);
for ( ; $i < $accept_l ; $i++ )
if ( ($t = strpos($s, $accept{$i})) !== FALSE )
if ( ($r === FALSE) || ($t < $r) )
$r = $t;
return $v;
}
?>