sqlite_current

SQLiteResult::current

SQLiteUnbuffered::current

(PHP 5 < 5.4.0, PECL sqlite >= 1.0.0)

sqlite_current -- SQLiteResult::current -- SQLiteUnbuffered::currentFetches the current row from a result set as an array

说明

array sqlite_current ( resource $result [, int $result_type = SQLITE_BOTH [, bool $decode_binary = true ]] )

面向对象风格 (method):

array SQLiteResult::current ([ int $result_type = SQLITE_BOTH [, bool $decode_binary = true ]] )
array SQLiteUnbuffered::current ([ int $result_type = SQLITE_BOTH [, bool $decode_binary = true ]] )

sqlite_current() is identical to sqlite_fetch_array() except that it does not advance to the next row prior to returning the data; it returns the data from the current position only.

参数

result

The SQLite result resource. This parameter is not required when using the object-oriented method.

result_type

可选的 result_type 参数接受常量,且决定返回的数组如何被索引。使用 SQLITE_ASSOC 会仅返回关联索引(已命名字段),而 SQLITE_NUM 会仅返回数值索引。SQLITE_BOTH 会同时返回关联和数值索引。SQLITE_BOTH 是此函数的默认值。

decode_binary

decode_binary 参数设置为 TRUE(默认值)时,PHP 会解码那些由 sqlite_escape_string() 编码后的二进制数据。通常应保留此值为其默认值,除非要与其他使用 SQLlite 的应用程序建立的数据交互。

返回值

Returns an array of the current row from a result set; FALSE if the current position is beyond the final row.

SQLITE_ASSOCSQLITE_BOTH 返回的列名会依照 sqlite.assoc_case 配置选项的值决定大小写。

参见

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