list

(PHP 4, PHP 5, PHP 7)

list — 把数组中的值赋给一组变量

说明

array list ( mixed $var1 [, mixed $... ] )

像 array() 一样，这不是真正的函数，而是语言结构。 list() 可以在单次操作内就为一组变量赋值。

Note:

list() 仅能用于数字索引的数组，并假定数字索引从 0 开始。

Warning

PHP 5 里，list() 从最右边的参数开始赋值； PHP 7 里，list() 从最左边的参数开始赋值。

如果你用单纯的变量，不用担心这一点。 但是如果你用了具有索引的数组，通常你期望得到的结果和在 list() 中写的一样是从左到右的，但在 PHP 5 里实际上不是， 它是以相反顺序赋值的。

通常而言，不建议依赖于操作的顺序，在未来可能会再次发生修改。

Warning

在 list() 执行过程中修改数组（比如使用 list($a, $b) = $b）将会产生不可预知的结果。

参数

var1

一个变量。

返回值

返回指定的数组。

范例

Example #1 list() 例子

<?php

$info = array('coffee', 'brown', 'caffeine');

// 列出所有变量
list($drink, $color, $power) = $info;
echo "$drink is $color and $power makes it special.\n";

// 列出他们的其中一个
list($drink, , $power) = $info;
echo "$drink has $power.\n";

// 或者让我们跳到仅第三个
list( , , $power) = $info;
echo "I need $power!\n";

// list() 不能对字符串起作用
list($bar) = "abcde";
var_dump($bar); // NULL
?>

Example #2 list() 用法的一个例子

<table>
 <tr>
  <th>Employee name</th>
  <th>Salary</th>
 </tr>

<?php

$result = $pdo->query("SELECT id, name, salary FROM employees");
while (list($id, $name, $salary) = $result->fetch(PDO::FETCH_NUM)) {
    echo " <tr>\n" .
          "  <td><a href=\"info.php?id=$id\">$name</a></td>\n" .
          "  <td>$salary</td>\n" .
          " </tr>\n";
}


?>

</table>

Example #3 使用嵌套的 list()

<?php

list($a, list($b, $c)) = array(1, array(2, 3));

var_dump($a, $b, $c);

?> 
int(1)
int(2)
int(3)

Example #4 在 list() 中使用数组索引

<?php

$info = array('coffee', 'brown', 'caffeine');

list($a[0], $a[1], $a[2]) = $info;

var_dump($a);

?>

产生如下输出（注意单元顺序和 list() 语法中所写的顺序的比较）：

Output of the above example in PHP 7:

array(3) {
  [0]=>
  string(6) "coffee"
  [1]=>
  string(5) "brown"
  [2]=>
  string(8) "caffeine"
}

Output of the above example in PHP 5:

array(3) {
  [2]=>
  string(8) "caffeine"
  [1]=>
  string(5) "brown"
  [0]=>
  string(6) "coffee"
}

Example #5 list() 和索引顺序定义

list() 使用 array 索引的顺序和它何时定义无关。

<?php
$foo = array(2 => 'a', 'foo' => 'b', 0 => 'c');
$foo[1] = 'd';
list($x, $y, $z) = $foo;
var_dump($foo, $x, $y, $z);

得到以下输出（注意比较 list() 所写的元素顺序）： 

array(4) {
  [2]=>
  string(1) "a"
  ["foo"]=>
  string(1) "b"
  [0]=>
  string(1) "c"
  [1]=>
  string(1) "d"
}
string(1) "c"
string(1) "d"
string(1) "a"

参见

  • each() - 返回数组中当前的键／值对并将数组指针向前移动一步
  • array() - 新建一个数组
  • extract() - 从数组中将变量导入到当前的符号表

User Contributed Notes

blazej 31-Aug-2017 11:00
From PHP Version 7.1 you can specify keys in list(), or its new shorthand [] syntax. This enables destructuring of arrays with non-integer or non-sequential keys.

<?php
$data = [
    ["id" => 1, "name" => 'Tom'],
    ["id" => 2, "name" => 'Fred'],
];

// list() style
list("id" => $id1, "name" => $name1) = $data[0];

// [] style
["id" => $id1, "name" => $name1] = $data[0];

// list() style
foreach ($data as list("id" => $id, "name" => $name)) {
    // logic here with $id and $name
}

// [] style
foreach ($data as ["id" => $id, "name" => $name]) {
    // logic here with $id and $name
}
grzeniufication 28-May-2017 01:01
<?php
/**
 * It seems you can skip listed values.
 * Here's an example to show what I mean.
 *
 * FYI works just as well with PHP 7.1 shorthand list syntax.
 * Tested against PHP 5.6.30, 7.1.5
 */
$a = [ 1, 2, 3, 4 ];

// this is quite normal use case for list
echo "Unpack all values\n";
list($v1, $v2, $v3, $v4) = $a;
echo "$v1, $v2, $v3, $v4\n";
unset($v1, $v2, $v3, $v4);

// this is what I mean:
echo "Skip middle\n";
list($v1, , , $v4) = $a;
echo "$v1, $v2, $v3, $v4\n";
unset($v1, $v2, $v3, $v4);

echo "Skip beginning\n";
list( , , $v3, $v4) = $a;
echo "$v1, $v2, $v3, $v4\n";
unset($v1, $v2, $v3, $v4);

echo "Skip end\n";
list($v1, $v2, , ) = $a;
echo "$v1, $v2, $v3, $v4\n";
unset($v1, $v2, $v3, $v4);

echo "Leave middle\n";
list( , $v2, $v3, ) = $a;
echo "$v1, $v2, $v3, $v4\n";
unset($v1, $v2, $v3, $v4);
Rhamnia Mohamed 17-May-2017 08:37
Since PHP 7.1, keys can be specified

exemple :
<?php
$array = ['locality' => 'Tunis', 'postal_code' => '1110'];

list('postal_code' => $zipCode, 'locality' => $locality) = $array;

print $zipCode; // will output 1110
print $locality; // will output Tunis
 ?>
carlosv775 at gmail dot com 13-Jan-2017 05:30
In PHP 7.1 we can do the following:

<?php
    [$a, $b, $c] = ['a', 'b', 'c'];
?>

Before, we had to do:

<?php
    list($a, $b, $c) = ['a', 'b',  'c'];
?>
anthony dot ossent at live dot fr 23-Oct-2016 12:04
a simple example of use to swap two variables :

$a = 'hello';
$b = 'world';

list($a, $b) = [$b, $a];

echo $a . ' ' . $b; //display "world hello"

another example :

function getPosition($x, $y, $z)
{
   // ... some operations like $x++...
   return [$x, $y, $z];
}

list($x, $y, $z) = getPosition($x ,$y, $z);
pemapmodder1970 at gmail dot com 06-Feb-2016 01:08
list() can be used with foreach

<?php
$array = [[1, 2], [3, 4], [5, 6]];

foreach($array as list($odd, $even)){
    echo "$odd is odd; $even is even", PHP_EOL;
}
?>

The output:
===
1 is odd; 2 is even
3 is odd; 4 is even
5 is odd; 6 is even
Dean 11-Dec-2015 04:20
UNDOCUMENTED BEHAVIOR:

    list($a,$b,$c) = null;

in fact works like:

    $a = null; $b = null; $c = null;

...So correspondingly:

    list($rows[]) = null;

Will increment count($rows), just as if you had executed $rows[] = null;

Watch out for this (for example) when retrieving entire tables from a database, e.g.

    while (list($rows[]) = $mysqlresult->fetch_row());

This will leave an extra 'null' entry as the last element of $rows.
Colin Guthrie 20-Jul-2015 10:41
If you want use the undefined behaviour as you might expect it e.g. if you want:

  $b = ['a','b']; list($a, $b) = $b;

to result in $a=='a' and $b=='b', then you can just cast $b to an array (even although it already is) to create a copy. e.g.

  $b = ['a','b']; list($a, $b) = (array)$b;

and get the expected results.
mogwai512 21-Jun-2015 02:54
I see many people offer solutions about the flipped order of the list construct. All you have to do is this:

<?php

$info = array('coffee', 'brown', 'caffeine');

$a = list($a[0], $a[1], $a[2]) = $info;

var_dump($a);

?>

. . . and your info will be in the correct order. You can also just assign a new var to the list and it will still work:

<?php

$info = array('coffee', 'brown', 'caffeine');

$b = list($a[0], $a[1], $a[2]) = $info;

var_dump($b);

?>
grzeniufication 21-Oct-2014 07:35
The example showing that:

$info = array('kawa', 'br?zowa', 'kofeina');
list($a[0], $a[1], $a[2]) = $info;
var_dump($a);

outputs:
array(3) {
[2]=>
string(8) "kofeina"
[1]=>
string(5) "br?zowa"
[0]=>
string(6) "kawa"
}

One thing to note here is that if you define the array earlier, e.g.:
$a = [0, 0, 0];

the indexes will be kept in the correct order:

array(3) {
  [0]=>
  string(4) "kawa"
  [1]=>
  string(8) "br?zowa"
  [2]=>
  string(7) "kofeina"
}

Thought that it was worth mentioning.
vickyssj7 at gmail dot com 02-Sep-2014 02:21
if we assign array's each value individual key('numeric only'), and use the array indices in list(),, then it output the reverse order of array keys--
BUT THE HIGHER KEY VALUE ("2" in this e.g below) WILL GET THE FIRST PLACE IN THE ARRAY IN RETURN, MEANS IT PUSHES THE VALUE WITH HIGHER KEY IN PLACE OF FIRST KEY VALUE, so it also gives higher key value the first priority while reversing the order of the keys and replacing the lower key value with the higher key value.

        $value = array( 0 => 'low', 2 => 'medium', 1 => 'higher');
        list($a[2], $a[1], $a[0]) = $value;
    var_dump($a);

//Outputs:---
array(3) {
            [0] => string(6) "medium"
            [1]  => string(6) "higher"
            [2]  => string(3) "low"
}
john at jbwalker dot com 08-Dec-2013 09:31
The list construct seems to look for a sequential list of indexes rather taking elements in sequence. What that obscure statement means is that if you unset an element, list will not simply jump to the next element and assign that to the variable but will treat the missing element as a null or empty variable:

    $test = array("a","b","c","d");
    unset($test[1]);
    list($a,$b,$c)=$test;
    print "\$a='$a' \$b='$b' \$c='$c'<BR>";

results in:
$a='a' $b='' $c='c'

not:
$a='a' $b='c' $c='d'
megan at voices dot com 11-Sep-2013 12:45
As noted, list() will give an error if the input array is too short. This can be avoided by array_merge()'ing in some default values. For example:

<?php
$parameter = 'name';
list( $a, $b ) = array_merge( explode( '=', $parameter ), array( true ) );
?>

However, you will have to array_merge with an array long enough to ensure there are enough elements (if $parameter is empty, the code above would still error).

An alternate approach would be to use array_pad on the array to ensure its length (if all the defaults you need to add are the same).

<?php
    $parameter = 'bob-12345';
    list( $name, $id, $fav_color, $age ) = array_pad( explode( '-', $parameter ), 4, '' );
    var_dump($name, $id, $fav_color, $age);
/* outputs
string(3) "bob"
string(5) "12345"
string(0) ""
string(0) ""
*/
?>
Achilles at thegreatwarrior dot com 14-Jul-2013 09:58
Second, when you're using the list() function, you must acknowledge each array element. You could not do this
list($weekday, $month) = $date;

But you can use empty values to ignore elements:
list ($weekday, , $month) = $date;
svennd 24-Dec-2012 04:08
The list() definition won't throw an error if your array is longer then defined list.
<?php

list($a, $b, $c) = array("a", "b", "c", "d");

var_dump($a); // a
var_dump($b); // b
var_dump($c); // c
?>
chris at chlab dot ch 08-Nov-2012 12:00
The example states the following:
<?php
// list() doesn't work with strings
list($bar) = "abcde";
var_dump($bar);
// output: NULL
?>

If the string is in a variable however, it seems using list() will treat the string as an array:
<?php
$string = "abcde";
list($foo) = $string;
var_dump($foo);
// output: string(1) "a"
?>