(PHP 5, PHP 7)
ibase_gen_id — Increments the named generator and returns its new value
$generator
[, int $increment = 1
[, resource $link_identifier = NULL
]] )本函数还未编写文档，仅有参数列表。
Returns new generator value as integer, or as string if the value is too big.
EXAMPLE:
You need to know the generator′s value after INSERT:
Before INSERT-Statement run
$nextnumber=ibase_gen_id ("GEN_NAME",1);
GEN_NAME: is the generator′s name
1: means add 1 to actual value of generator
$nextnumber: is variable to store generators value after incrementing
In the INSERT-Statement you can use $nextnumber instead of using generator directly like in:
INSERT INTO test (field1, field2) VALUES gen_id(gen_test_id, 1), 'testme');
$sql="INSERT INTO mitabla(campo1,campo2,..campo n) VALUES(GEN_ID(mitabla1_codigo_gen,1),'contenido 1', 'contenido 2', 'contenido n' )";
Question arose on php-dev:
How does ibase_gen_id() handle 64bit values?
Interbase 6/Firebird generators are always 64-bit signed integers
(Firebird's BIGINT type), regardless of the platform the client is
running.
On 64-bit platforms, this will never require conversion as PHP's int
type is 64 bits wide on those platforms. On 32-bit platforms, the
generated value is converted to a string if it exceeds the limits of a
32-bit signed integer.
(This behaviour is consistent with the ibase_fetch_*() functions, that
will use strings to represent numerical values that cannot be represented
accurately using native PHP numerical types.)
[Edited by PHP/Interbase maintainer.]