class_alias

(PHP 5 >= 5.3.0, PHP 7)

class_alias — 为一个类创建别名

说明

bool class_alias ( string $original , string $alias [, bool $autoload = TRUE ] )

基于用户定义的类 original 创建别名 alias。 这个别名类和原有的类完全相同。

参数

original

原有的类。

alias

类的别名。

autoload

如果原始类没有加载，是否使用自动加载（autoload）。

返回值

成功时返回 TRUE， 或者在失败时返回 FALSE。

范例

Example #1 class_alias() 例子

<?php

class foo { }

class_alias('foo', 'bar');

$a = new foo;
$b = new bar;

// the objects are the same
var_dump($a == $b, $a === $b);
var_dump($a instanceof $b);

// the classes are the same
var_dump($a instanceof foo);
var_dump($a instanceof bar);

var_dump($b instanceof foo);
var_dump($b instanceof bar);

?>

以上例程会输出：

bool(true)
bool(false)
bool(true)
bool(true)
bool(true)
bool(true)
bool(true)

参见

User Contributed Notes

sofe2038 at gmail dot com 08-Jan-2017 01:06
Doesn't work with coupled classes when used along with autoloading.

For example, in these classes where each class is autoloaded in a separate class file:

Foo.php:

<?php
interface Foo{
  public function fx(Bar $bar);
}
?>

Bar2.php:

<?php
class Bar2 implements Foo{
  public function fx(Bar2 $bar){
    // some implementation code here
  }
}
?>

Bar.php:

<?php
class_alias("Bar2", "Bar");
?>

When used with an autoloader like this:

<?php
spl_autoload_register(function($class){
  require($class . ".php");
});
new Bar;
?>

Results in fatal error:

    Declaration of Bar2::fx(Bar2 $bar) must be compatible with Foo::fx(Bar $bar) in ~/Bar2.php on line 2
sofe2038 at gmail dot com 08-Jan-2017 01:06
Doesn't work with coupled classes when used along with autoloading.

For example, in these classes where each class is autoloaded in a separate class file:

Foo.php:

<?php
interface Foo{
  public function fx(Bar $bar);
}
?>

Bar2.php:

<?php
class Bar2 implements Foo{
  public function fx(Bar2 $bar){
    // some implementation code here
  }
}
?>

Bar.php:

<?php
class_alias("Bar2", "Bar");
?>

When used with an autoloader like this:

<?php
spl_autoload_register(function($class){
  require($class . ".php");
});
new Bar;
?>

Results in fatal error:

    Declaration of Bar2::fx(Bar2 $bar) must be compatible with Foo::fx(Bar $bar) in ~/Bar2.php on line 2
robsonvnasc at gmail dot com 22-Sep-2016 12:30
It also works with Traits!

<?php
trait Foo {}
class_alias("Foo","Bar");
echo trait_exists("Bar") ? 'yes' : 'no';
?>
//yes
stanislav dot eckert at vizson dot de 15-Sep-2015 04:00
class_alias() creates aliases only for user defined classes, not for classes supplied by PHP (PHP will show the warning "First argument of class_alias() must be a name of user defined class"). To create aliases for every kind of classes, use namespaces:

<?php

// Does not work
class_alias("ZipArchive", "myZip");

// Creates class alias "myZip" of class "ZipArchive"
use \ZipArchive as myZip;

?>
petar dot karan dot pk at gmail dot com 06-Feb-2014 11:19
If you need the same function in PHP version < 5.3 you can use this

<?php
function class_alias($original,$alias) {
    $newclass = create_function('','class '.$alias.' extends '.$original.' {}');
    $newclass();
}
?>
mweierophinney at gmail dot com 06-Mar-2013 11:05
class_alias() gives you the ability to do conditional imports.

Whereas the following will not work:

<?php
namespace Component;

if (version_compare(PHP_VERSION, '5.4.0', 'gte')) {
    use My\ArrayObject;
} else {
    use ArrayObject;
}

class Container extends ArrayObject
{
}
?>

the following, using class_alias, will:

<?php
namespace Component;

if (version_compare(PHP_VERSION, '5.4.0', 'lt')) {
    class_alias('My\ArrayObject', 'Component\ArrayObject');
} else {
    class_alias('ArrayObject', 'Component\ArrayObject');
}

class Container extends ArrayObject
{
}
?>

The semantics are slightly different (I'm now indicating that Container extends from an ArrayObject implementation in the same namespace), but the overall idea is the same: conditional imports.
sergey dot karavay at gmail dot com 25-Feb-2013 08:08
At first, you might wonder that:
<?php class A {}; class_alias('A', 'B'); ?>

is equivalent to:
<?php class A {}; class B extends A {}; ?>

class_alias is NOT equivalent to class extending! Private methods/properties are unseen in child classes, but in alias classes they are.
Anonymous 13-Feb-2013 02:42
Like class_alias but for functions:

<?php
function function_alias ($original, $alias) {
 
  $args = func_get_args();
  assert('count($args) == 2', 'function_alias() require exactly two arguments');
  assert('is_string($original) && is_string($alias)', 'function_alias() require string arguments');
 
  // valid function name - http://php.net/manual/en/functions.user-defined.php
  assert('preg_match(\'/^[a-zA-Z_\x7f-\xff][\\\\\\\\a-zA-Z0-9_\x7f-\xff]*$/\', $original) > 0',
    "'$original' is not a valid function name");
  assert('preg_match(\'/^[a-zA-Z_\x7f-\xff][\\\\\\\\a-zA-Z0-9_\x7f-\xff]*$/\', $alias) > 0',
    "'$alias' is not a valid function name");
 
  $aliasNamespace = substr($alias, 0, strrpos($alias, '\\') !== false ? strrpos($alias, '\\') : 0);
  $aliasName = substr($alias, strrpos($alias, '\\') !== false ? strrpos($alias, '\\') + 1 : 0);
  $serializedOriginal = var_export($original, true);
 
  eval("
    namespace $aliasNamespace {
      function $aliasName () {
        return call_user_func_array($serializedOriginal, func_get_args());
      }
    }
  ");
 
}

?>

Until hopefully function_alias is added to php...
adam at adamhahn dot com 06-Sep-2011 09:13
Something to note,

If the $original class has not yet been defined or loaded, the auto loader will be invoked in order to try and load it.

If the class for which you are trying to create an alias does not exist, or can not be loaded with the auto loader, you will generate a PHP Warning.
programmer-comfreek at hotmail dot com 15-Aug-2011 06:38
If you defined the class 'original' in a namespace, you will have to specify the namespace(s), too:
<?php
namespace ns1\ns2\ns3;

class A {}

class_alias('ns1\ns2\ns3\A', 'B');
/* or if you want B to exist in ns1\ns2\ns3 */
class_alias('ns1\ns2\ns3\A', 'ns1\ns2\ns3\B');
?>
nicolas dot grekas+php at gmail dot com 31-Dec-2010 10:09
At first, you might wonder that:
<?php class A {}; class_alias('A', 'B'); ?>

is equivalent to:
<?php class A {}; class B extends A {}; ?>

BUT when derivation creates a new class name - that means, you can then instantiate a new kind of objects - aliasing is just what it says: a synonym, so objects instantiated with the aliased name are of the exact same kind of objects instantiated with the non-aliased name.

See this code for example:
<?php
class A {};
class B1 extends A {};
class_alias('A', 'B2');

$b1 = new B1; echo get_class($b1); // prints B1
$b2 = new B2; echo get_class($b2); // prints A !
?>
nicolas dot grekas+php at gmail dot com 30-Dec-2010 11:41
class_alias also works for interfaces!

<?php
interface foo {}
class_alias('foo', 'bar');
echo interface_exists('bar') ? 'yes!' : 'no'; // prints yes!
?>