cal_days_in_month

(PHP 4 >= 4.1.0, PHP 5, PHP 7)

cal_days_in_month返回某个历法中某年中某月的天数

说明

int cal_days_in_month ( int $calendar , int $month , int $year )

该函数返回特定历法中的某中的某的天数。

参数

calendar

用来计算的某个历法

month

选定历法中的某月

year

选定历法中的某年

返回值

指定历法中选定的某月的天数。

范例

Example #1 cal_days_in_month() example

<?php
$num 
cal_days_in_month(CAL_GREGORIAN82003); // 31
echo "There was $num days in August 2003";
?>

User Contributed Notes

ejazahemed999 at gmail dot com 08-Feb-2017 02:14
Simplest one for string date like bellow;

      $date = '2017-01-28';
      echo date(' t ', strtotime($date) );

Output :
               31

strtotime() will convert string date to timestamp and date function will return specified format in this case ' t ' means total number of days in month.
XombyCraft at gmail dot com 31-Mar-2015 09:10
To get the number of days in a given month, you just need to pass a timestamp that occurs during that month to the date function.

I've found this is beneficial when I cannot guarantee a particular set of functionality has been compiled into a given PHP installation.

<?php
$month
= "2"
$year = "2014"
date("t",mktime(0,0,0,$month,1,$year));

//equivalent to
date("t",mktime(0,0,0,2,1,2014));
//returns 28
?>
p2409 at hotmail dot com 28-Oct-2013 02:09
If you have a DateTime variable you want to find the number of days in the month for, you can simply use $dt->format and the format specifiers 'm' and 'Y' to get the month digit, and year to use with cal_days_in_month eg.

function DaysInMonth($dt) {
    $m =  $dt->format('m');
    $y =  $dt->format('Y');
    $numDays = cal_days_in_month (CAL_GREGORIAN, $m,$y);
    return $numDays;
}
asifsajjad at gmail dot com 29-Jul-2013 12:05
count specific days in a month like how many satureday in a monday or how many mondays in a month
<?php

function my_cal_days_in_month($year,$month,$calday="1"){ //0 Sunday, 1 Monday, 2 Tue , 3 Wed , 4. Thu , 5. Fri , 6. Sat
    // calculate total number of occurance in this month
   
$num = cal_days_in_month(CAL_GREGORIAN, $month, $year); // days in month
   
$dayofweek = date( "w", mktime(0, 0, 0, $month, 1, $year));    
   
$adddays=0;
    if(
$calday > $dayofweek )
           
$adddays=1 + $calday - $dayofweek;
    else if(
$calday < $dayofweek )
           
$adddays=1 + 7 + ($calday - $dayofweek );
               
   
$remainingdays=$num-$adddays;
   
$leavesnum=1+intval($remainingdays / 7);
    return    
$leavesnum;
}

$year=2013;
$month=7;
$day=6;
echo
my_cal_days_in_month($year,$month,$day);
Anonymous 12-Nov-2011 12:51
You can also use the date() function to get the number of days in a month. You can also pass the 2nd param strtotime() and specify a specific date:

date('t');
adam.pippin at ohmedia.ca 15-Jun-2011 12:06
Forgot to compile the calendar plugin in... Wrote a workaround while I waited for it to compile. It only supports the Gregorian calendar.

<?php
if (!function_exists('cal_days_in_month'))
{
    function
cal_days_in_month($calendar, $month, $year)
    {
        return
date('t', mktime(0, 0, 0, $month, 1, $year));
    }
}
if (!
defined('CAL_GREGORIAN'))
   
define('CAL_GREGORIAN', 1);
?>
deva dot ananth at gmail dot com 10-Mar-2011 02:44
Function  for calculation number of days until birthday:

<?php
function daysLeftForBirthday($devabirthdate)
{
   
/* input birthday date format -> Y-m-d */
   
list($y, $m, $d) = explode('-',$devabirthdate);
   
$nowdate = mktime(0, 0, 0, date("m"), date("d"), date("Y"));
   
$nextbirthday = mktime(0,0,0,$m, $d, date("Y"));

    if (
$nextbirthday<$nowdate)
       
$nextbirthday=$nextbirthday+(60*60*24*365);

   
$daycount=intval(($nextbirthday-$nowdate)/(60*60*24));

    return
$daycount;
}
?>
brian at b5media dot com 05-Dec-2007 01:55
Remember if you just want the days in the current month, use the date function:
$days = date("t");
geko45pj at yahoo dot com 19-Jul-2007 08:28
<?php
# PHP Calendar (version 2.3), written by Keith Devens

function generate_calendar($year, $month, $days = array(), $day_name_length = 3, $month_href = NULL, $first_day = 0, $pn = array()){
   
$first_of_month = gmmktime(0,0,0,$month,1,$year);

   
#remember that mktime will automatically correct if invalid dates are entered
    # for instance, mktime(0,0,0,12,32,1997) will be the date for Jan 1, 1998
    # this provides a built in "rounding" feature to generate_calendar()

   
$day_names = array(); #generate all the day names according to the current locale
   
for($n=0,$t=(3+$first_day)*86400; $n<7; $n++,$t+=86400) #January 4, 1970 was a Sunday
       
$day_names[$n] = ucfirst(gmstrftime('%A',$t)); #%A means full textual day name

   
list($month, $year, $month_name, $weekday) = explode(',',gmstrftime('%m,%Y,%B,%w',$first_of_month));
   
$weekday = ($weekday + 7 - $first_day) % 7; #adjust for $first_day
   
$title   = htmlentities(ucfirst($month_name)).'&nbsp;'.$year#note that some locales don't capitalize month and day names

    #Begin calendar. Uses a real <caption>. See http://diveintomark.org/archives/2002/07/03
   
@list($p, $pl) = each($pn); @list($n, $nl) = each($pn); #previous and next links, if applicable
   
if($p) $p = '<span class="calendar-prev">'.($pl ? '<a href="'.htmlspecialchars($pl).'">'.$p.'</a>' : $p).'</span>&nbsp;';
    if(
$n) $n = '&nbsp;<span class="calendar-next">'.($nl ? '<a href="'.htmlspecialchars($nl).'">'.$n.'</a>' : $n).'</span>';
   
$calendar = '<table class="calendar">'."\n".
       
'<caption class="calendar-month">'.$p.($month_href ? '<a href="'.htmlspecialchars($month_href).'">'.$title.'</a>' : $title).$n."</caption>\n<tr>";

    if(
$day_name_length){ #if the day names should be shown ($day_name_length > 0)
        #if day_name_length is >3, the full name of the day will be printed
       
foreach($day_names as $d)
           
$calendar .= '<th abbr="'.htmlentities($d).'">'.htmlentities($day_name_length < 4 ? substr($d,0,$day_name_length) : $d).'</th>';
       
$calendar .= "</tr>\n<tr>";
    }

    if(
$weekday > 0) $calendar .= '<td colspan="'.$weekday.'">&nbsp;</td>'; #initial 'empty' days
   
for($day=1,$days_in_month=gmdate('t',$first_of_month); $day<=$days_in_month; $day++,$weekday++){
        if(
$weekday == 7){
           
$weekday   = 0; #start a new week
           
$calendar .= "</tr>\n<tr>";
        }
        if(isset(
$days[$day]) and is_array($days[$day])){
            @list(
$link, $classes, $content) = $days[$day];
            if(
is_null($content))  $content  = $day;
           
$calendar .= '<td'.($classes ? ' class="'.htmlspecialchars($classes).'">' : '>').
                (
$link ? '<a href="'.htmlspecialchars($link).'">'.$content.'</a>' : $content).'</td>';
        }
        else
$calendar .= "<td>$day</td>";
    }
    if(
$weekday != 7) $calendar .= '<td colspan="'.(7-$weekday).'">&nbsp;</td>'; #remaining "empty" days

   
return $calendar."</tr>\n</table>\n";
}
echo
generate_calendar(2010, 12, 16,3,NULL,0,15, $first_of_month, $day_names, $day_names[$n]);
#echo generate_calendar($year, $month, $days,$day_name_length,$month_href,$first_day,$pn);
?>
jeffbeall at comcast dot net 14-Apr-2004 07:04
This will work great in future dates but will give the wrong answer for dates before 1550 (approx) when leap year was introduced and the calendar lost a year or two.
Sorry now to be more specific it has been a while sine I had to account for those later dates and had to take that into account but just a heads up for others to watch out.
dbindel at austin dot rr dot com 02-Jan-2004 06:06
Here's a one-line function I just wrote to find the numbers of days in a month that doesn't depend on any other functions.

The reason I made this is because I just found out I forgot to compile PHP with support for calendars, and a class I'm writing for my website's open source section was broken. So rather than recompiling PHP (which I will get around to tomorrow I guess), I just wrote this function which should work just as well, and will always work without the requirement of PHP's calendar extension or any other PHP functions for that matter.

I learned the days of the month using the old knuckle & inbetween knuckle method, so that should explain the mod 7 part. :)

<?php
/*
 * days_in_month($month, $year)
 * Returns the number of days in a given month and year, taking into account leap years.
 *
 * $month: numeric month (integers 1-12)
 * $year: numeric year (any integer)
 *
 * Prec: $month is an integer between 1 and 12, inclusive, and $year is an integer.
 * Post: none
 */
// corrected by ben at sparkyb dot net
function days_in_month($month, $year)
{
// calculate number of days in a month
return $month == 2 ? ($year % 4 ? 28 : ($year % 100 ? 29 : ($year % 400 ? 28 : 29))) : (($month - 1) % 7 % 2 ? 30 : 31);
}
?>

Enjoy,
David Bindel